Features:
- The functionality can be a method.
- · The method is independent one.
- · This function is used anywhere whenever the program needs.
How to pass a lambda expression as a method argument in
java:
It can be
done many ways. Generally, we follow two methods.
1. 1. Using Runnable
2. 2.Using custom functional interface
1.Using Runnable :
This method
starts from creating a class “Main3” and
save the program as “Main3.java”. In the public static void main(), add the
lambda expression to print “Welcome to java Programming!”
Next, create a separate function execute with Runnable variable action.
Now, call action.run().
public class Main3 {
public static void
main(String[] args) {
//using a
lambda expression as a method argument.
execute(()
-> System.out.println("Welcome to java Programming!"));
}
public static void
execute(Runnable action) {
action.run();
}
}
This program gives you the below output.
2.Using custom functional interface
A functional
interface creates abstract method. Here, “condition” is the functional
interface. The abstract method is “find”. It has two integer arguments.
A class “Main4” is created. It passes a lambda expression as
argument. It adds two integer values.
Another function is created to call the lambda arguments.
Here, is the program.
interface condition {
int find(int x,
int y);
}
public class Main4 {
public static void
main(String[] args) {
// Passing a
lambda expression as a method argument
int res =
conditionChecking(45, 36, (x, y) -> x + y);
System.out.println("Result: " + res);
}
public static int
conditionChecking(int x, int y, Operation operation) {
return
operation.find(x, y);
}
}
While executing this program, you get the below output.
These are the ways to pass a lambda expression as a method argument in java.
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